1MA1 Practice papers Set 6: Paper 2F (Regular) mark scheme – Version 1.0
Question	Working	Answer	Mark	Notes
1	1	B1 for or an equivalent fraction
2	0.17	1	B1 cao
3	2	M1 for oe , A1 cao
4	18	2	M1for 24 ÷ 4× 3 oe A1 cao
5	125	2	M1 for complete method using graph eg 50 euros = £42; 42 × 3 A1 for 122 – 128
6	36	1	B1 cao for Cazda
120°	1	B1 cao for Zusuki
42	2	M1 for correct method from using 105° e.g. 18 ÷ 45 × 105, “36” ÷ 90 × 105 or from table, e.g. Cazda “36” × 4−(18+36+48) A1 for 42 or ft values from their table.
7	Jane should buy Greens Garden Shop + costs	4	M1 for Suttons: 140 ÷ 20 (= 7) bags of compost needed M1 for 3 × 3.25 (= 9.75) + 1 × 2.25 (=12) M1 for Greens: cost of 2 bags eg × 4.99 (= 9.98) , 2 × 5 (=10) C1 for correct conclusion from a comparison of correct appropriate figures
8	(a)	25	1	B1 cao
(b)	yes with correct comparative figures	3	M1 for method to calculate journey time travelling at 30 mph, eg (=0.66…) or 40 (mins) M1 (dep) for method to work out arrival time at home, (consistent units), eg 18 10 + “40 mins” (=18 50) C1 for yes with comparison of 40 minutes with 50 minutes or stating arrival time home as 18 50 OR M1 for method to calculate speed in order to get home by 1900 eg 20 ÷ (= 24 mph) M1 (dep) for stating speed as 24 mph C1 for yes with supporting calculations showing speed as 24 mph
9	(a)	4 × 3	12	1	B1 cao
(b)	5	2	M1 for 4 × 2 – 3 A1 cao
10	(a)	37, 41	2	B1 for 37; B1 for 41
(b)	e.g added 4; +4	1	B1 for sight of 4n + 13
(c)	61	1	B1 cao
(d)	e.g. even number all numbers in sequence are odd	1	B1 69, 73 are in the sequence or solution of 4n + 13 = 70 does not give an integer
11	143.64 19 = 7.56 7.56 31 =	234.36	3	M1 for 143.64 19 (or 7.56 seen) or 143.64 31 (or 4452.84 seen) M1(dep) for ‘7.56’ 31 or ‘4452.84’ 19 or 143.64 + 12’7.56’ A1 for 234.36 cao accept 234.36p Alternative method: M1 for (or 1.63(1…) seen) M1 (dep) ‘1.63…’ × 143.64 A1 for 234.36 cao accept 234.36p
12	(a)	iPh Smart phone 838 DVDs 4 × 16 = 64 Lawnmower 57 ÷ 3 × 12 = 19 × 12 = 228 838 + 64 + 228 = 1130 20	1130	3	M1 for 57 ÷ 3 × 12 or 228 seen M1 for 838 + 4 × 16 + ‘57 ÷ 3 × 12’ A1 cao (b
(b)	4500 ÷ 500 = 9 9 × 2.40 = 21.60 Or 22 ÷ 2.40 = 9.1666... 9.1666... × 500 = 4583.33... Or £2.40 needs 500 points £24 needs 5000 points 24 – 2.40 needs 4500 points £21.60 needs 4500 points	No with explanation	4	M1 for 4500 ÷ 500 ( = 9) (maybe implied by 9 lots of 500 seen) M1 for ‘9’ × 2.40 A1 cao for 21.60 C1 (dep on M1) f.t. for ‘No’ Decision must be stated and must be attributable from a correct method. M1 for 22 ÷ 2.40 ( = 9.1666) Or M1 for ‘22 ÷ 2.40’ × 500 A1 for answer in range 4583 to 4583.33.... C1 (dep on M1) f.t. for ‘No’ Decision must be stated and must be attributable from a correct method. Or M1 for £24 (or 2400p) = 5000 M1 for 24 – 2.40 (or 2400 – 240) = 4500 A1 cao for 21.60 C1 (dep on M1) f.t. for ‘No’ Decision must be stated and must be attributable from a correct method.
13	(a)	50 < a ≤ 60	1	B1 for correctly identifying the modal class interval e.g. 50 – 60 oe
(b)	Polygon	2	B2 for fully correct frequency polygon - points plotted at the midpoint (B1 for all points plotted accurately but not joined with straight line segments or all points plotted accurately and joined with last joined to first to make a polygon or all points at the correct heights and consistently within or at the ends of the intervals and joined (can include joining last to first to make a polygon)
14	60 – 29 = 31 13 – 8 = 5 31 – 10 – 5 = 16 Th C It W 6 15 8 29 M 16 10 5 31 22 25 13 60	16	4	M1 for calculation of total Men 60 – 29 (= 31 Men) M1 for calculation for Men who like Italian 13 – 8 (= 5 Men like Italian) M1 for calculation for Men who liked Thai ‘31’ – 10 – ‘5’ A1 for 16 OR M1 for a 2-way table or diagram with clear labelling showing at least 3 pieces of the given information correctly placed M1 for correct method for one calculated entry in diagram: Men 60–29(=31) or Women and Chinese 29–8–6 (= 15) or Men and Italian 13–8 (= 5) M1 for 3 correct entries for Men or 2 correct entries for Thai that with correct arithmetic would lead to 16 (Men and Thai) A1 for 16
15	(7 + 3 + 3) × (4 + 3 + 3) – 7 × 4 = 102 or 2 × 7 × 3 + 2 × 4 × 3 + 4 × 3 × 3 = 102	11	4	M1 for a correct method to find the area of one appropriate rectangle M1 for a complete method to find the area of the path M1 (dep on M1) for “102” ÷ 10 A1 cao
16	(a)	Evens	1	B1 cao
Certain	1	B1 cao
(b)	4	2	M1 for 14 or or any fraction equivalent to or A1 cao
17	(a)	A and C	1	B1 for A and C (no extras)
(b)	B or E	1	B1 for B or E (or both) (no extras)
(c)	2	1	B1 cao
18	77	3	M1 for 21 ÷ 6 (= 3.5) for sf length or 21 ÷ 6 × 5 (=17.5) M1 for 3×”3.5” + 3×”3.5” + 21 + 21 or 17.5+17.5+21+21 oe A1 cao OR M1 for 21÷6 (=3.5) for sf length M1 for (6+5+6+5)×”3.5” or 22×3.5 oe A1 cao
19	x + x + 4 + 3(x + 4) = 51 2x + 4 + 3x + 12 = 51 5x + 16 = 51 5x = 35 5x = 35 ÷ 5	Ann 7 Beth 11 Cath 33	5	M1 for x + 4 or 3(x + 4) oe seen M1 for x + ‘x + 4’ + ‘3(x + 4)’ M1 x + ‘x + 4’ + ‘3(x + 4)’ = 51 A1 for 7 or 11 or 33 C1 for Ann 7, Beth 11, and Cath 33 oe OR M1 for using a value for n, eg n + 4 or 4 × n M1 for attempting a trial using n, n + 4 and 3(n + 4) M1 for at least 2 trials with correct totals for ‘n’ A1 for 11 or 33 C1 for Ann 7, Beth 11, and Cath 33 oe
20	A and 3 B and 2 C and 4 D and 1	2	B2 for all 4 correct (B1 for 2 correct)
21	1 – (0.008 + 0.015)	0.977	2	M1 for 1 – (0.008 + 0.015) oe A1 for 0.977 oe
22	(a)	7.5	3	M1 for 4.5² + 6² (=56.25) M1 for √56.25 or √(4.5² + 6²) A1 for 7.5
(b)	217	4	M1 for use of appropriate trig ratio, e.g. tan CAB = ( = 0.75), sin CAB = ( = 0.6), cos CAB = ( = 0.8) M1 for inverse trig shown correctly, e.g. CAB = tan−1 (= 0.75), CAB = sin−1 ( = 0.6), CAB = cos−1 ( = 0.8) A1 for 36.8 to 37 (or 53 to 53.2 if identified as ACB) B1ft for bearing 180 + “36.8” if “36.8” is not 40–50, e.g. 216.8 to 217
23	16 × 7 = 112 112 - 87	25	2	M1 for 6 × 14.5 (= 87) or 7 × 16 (=112) or 6 × 1.5 (= 9) or 7 × 1.5 (= 10.5) A1 for 25
24	126	3	M1 for 180 – (360 ÷ 5) (= 108) or (5 – 2) × 180 ÷ 5 (= 108) M1 for a complete method eg or A1 cao

National performance data from Results Plus

Original source of questions	Mean score of students achieving grade:
Qn	Spec	Paper	Session YYMM	Qn	Topic	Max score	ALL	C	D	E	F	G
1	5MM2	2F	1306	Q09a	Fractions	1	0.80	0.99	0.98	0.96	0.88	0.80
2	5MM2	2F	1306	Q09b	Decimals	1	0.82	0.96	0.95	0.91	0.75	0.70
3	5MM2	2F	1306	Q09c	Fractions	2	1.61	0.73	0.48	0.37	0.33	0.34
4	5MM2	2F	1306	Q09d	Fractions	2	1.38	0.95	0.90	0.86	0.76	0.68
5	1MA0	2F	1611	Q15b	Conversions	2	Data to be added in January 2017
6	1MA0	2F	1611	Q8	Pie charts	4	Data to be added in January 2017
7	1MA0	2F	1611	Q10	Ratio	4	Data to be added in January 2017
8	1MA0	2F	1611	Q21	Compound measures	4	Data to be added in January 2017
9	1MA0	2F	1306	Q08	Substitute into expressions	3	1.78	2.88	2.59	1.96	1.08	0.46
10	4MA0(R)	1F	1501	Q05	Sequences	5	4.53	4.76	4.61	4.66	4.00	1.00
11	1380	2H	906	Q05	Decimals	3	2.88	2.83	2.59	2.00
12	5AM2	2F	1211	Q20	Ratio	7	5.26	6.45	5.97	5.27	3.52	1.53
13	1MA0	1F	1611	Q22	Grouped frequency	3	Data to be added in January 2017
14	5AM1	1H	1306	Q13	Two-way tables	4	3.66	3.56	2.96	1.62
15	1MA0	1F	1611	Q23	Area	4	Data to be added in January 2017
16	1MA0	2F	1311	Q16	Probability	4	2.37	3.23	2.63	2.15	1.80	1.51
17	1MA0	2F	1211	Q13	Congruence and similarity	3	1.73	2.37	1.96	1.65	1.35	0.98
18	5AM2	2H	1411	Q05	Scale factors	3	2.28	2.11	1.21	1.00
19	5AM1	1H	1211	Q09	Solve linear equations	5	3.87	3.48	2.73
20	1380	2H	1011	Q11	Distance-time / travel graphs	2	0.89	0.77	0.66	0.57
21	5AM2	2H	1111	Q06	Probability	2	1.47	1.62	1.00	0.00	0.00	0.00
22	1MA0	2H	1406	Q15	Pythagoras in 2D	7	2.91	2.16	0.88	0.20
23	1380	2H	1203	Q02	Mean, median, mode	2	0.71	0.45	0.14	0.07
24	1MA0	2H	1611	Q14	Angles	3	Data to be added in January 2017
TOTAL	80